it is very easy just simplyfi a bit the expression will become
sin8A/sin2A from there apply sin2θ=2sinθcosθ and after cancelling the terms you will get the answer
Proof that
(tan5A+tan3A)/(tan5A-tan3A)=4cos4Acos2A
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2 Answers
Amartya Kumar Mistry
·2014-06-30 22:25:57
Yash Sachdev
·2016-08-23 22:52:33
Cant understand answer please write and show but my question is bit different tan5A-tan3A/tan5A-tan3A=sin2A/sin8A