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Let ABC e x° and EDC=y° as shown
as AB = AC
so ACB = x°
AED=(x+y)° as it is the exterior angle
so ADE=(x+y)° as AD=AE
so ADC=(x+2y)°
but ADC=(30+x)°..
so 30+x=x+2y..
so 2y=30°
y=15°
so ans is sin 15°
In the given triangle LBAD = 30° , AB = AC and AD = AE then find the value of
sin LEDC.
level A sitter question :P
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