Solve.......

JEE Main 2015 Sample Questions › Trignometry questions › Solve.......

Solve.
1.
log_{((9x-x²-14)/7)}(sin3x-sinx)=log_{((9x-x²-14)/7)}cos2x

2.
2cos²(pi4^x)-sin(pi4^x+1)+sin(pi4^x+1/2)-2cos(pi4^x+1/2)=0

#Mathematics #Trignometry

UP 0 DOWN 0 0 7
Post on FacebookPost anonymously?

7 Answers

1

skygirl ·2008-10-23 20:05:30

q1.) is the ans x=5Ï€/6 and x=13Ï€/6 ???

q2.) is the question corect??

UP 0 DOWN 0
Post on FacebookPost anonymously?

33

Abhishek Priyam ·2008-10-25 20:46:32

Q.1 absolutly correct...

UP 0 DOWN 0
Post on FacebookPost anonymously?

33

Abhishek Priyam ·2008-10-25 20:47:16

Try taking pi4^x as y....

UP 0 DOWN 0
Post on FacebookPost anonymously?

33

Abhishek Priyam ·2008-10-25 20:49:18

the eqn becomes....

2cos²(y)-sin(4y)+sin(2y)-2cos(2y)=0

where y=pi4^x

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

skygirl ·2008-10-25 20:49:39

ya ya tried dat way only but may b i have copied sumthing wrong

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

skygirl ·2008-10-25 20:50:52

chhodo.........i will let u know later... now pc on ups... :(

UP 0 DOWN 0
Post on FacebookPost anonymously?

33

Abhishek Priyam ·2008-10-25 20:51:20

Ok leave it it involves only calculation as 4y is involved so a lot of calculation.....

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω