solve.

sin^-112x +sin^-112√3x=t
sin(sin^-112x +sin^-112√3x)=sin t

now this should be fairly simple try once...

nothing too much :)

1= this value!

take 12x = k

k/√1-3k²+√3k/√1-k² = 1

take square

k²/(1-3k²) + 3k²/(1-k²) = 1

k²{1/(1-3k²) + 3/(1-k²)} = 1

now i dont think there is too much...

just keep in mind.. in such problems, you could find some "extra" roots which may not satisfy... this is because we have taken square and sin... so it is necessary to verify and remove such roots....