1I am getting tan2β2.tan2θ2=tan2α2
COSθ=COSα-COSβ/1-COSαCOSβ.
THEN TAN2(θ/2).TAN2(β/2)=?
PLEASE GIVE A DETAILED SOLUTION.
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3 Answers
36The solution is really detailed, i can give you the solution but first of all let me verify myself
Is it, {(1 - COSα)2.(1 + COSθ).(1 + COSβ)/Sin2α.sinθ.sinβ} ???????????...........
11simply apply cosθ=1-tan2θ/2/1+tan2θ/2
u get the required result.
i thinksaikat007 answer should be the one.