Trigno Doubt(S)

sorryy made a silly mistake !!!!
answer is c only
see tushar
1.1 =1
-1 . -1 =1
now how many times sin achieves 1or -1 in 0 - 3 pi ?
at pi/2 (1) ,3 pi/2 (-1),5pi/2 (1)
now come to cosine
now how many times cosin achieves 1 or -1 in 0 - 3 pi ?
at 0 (1),pi(-1),2pi(1),3pi(-1)

now do permutation of possible cases
in 2 ways i can choose 1 fom cosine
and 2 ways from sin
so
simultaneously the events can be done in

2*2=4

now in 2 ways i can chose -1 from cosine

and 1 way from sin
so

simultaneously the events can be done in

2*1 =2

adding up the cases

2+4 = 6

hence answer is 6

oh yes, thanx "light" [1]

yes the ans is (c)6 ..