1ya B is the rite ans.....
A+B+C=pie ( A,B,C>0) AND ANGLE C IS OBTUSE THEN
A) TAN A.TAN B >1
B) TAN A.TAN B <1
C) TAN A.TAN B =1
D) NONE OF THESE
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4 Answers
1A+B=PI-C
GETTING TAN BOTH SIDE
tanA+tanB/1-tanAtanB=-tanc
C IS OBTUSE .SO tan C IS NEGATIVE. WHOLE BECOME POSITIVE.
tanA+tanB POSITIVE.. SO 1-tanAtanB SHOULD BECOME POSITIVE....
1-tanAtanB>0
tanAtanB<1
ANSWER IS B
1prove that summation of (n-k)cos2kpi/n=-n/2...when n is greater than equal to 3i is an integer.the limit of the summation is fromk=1 to ( n-1).