\because \csc^2 \theta \ge 1 we have
LHS = 4 \csc^2 (\pi(a+x)) + a^2-4a \ge a^2-4a+4 = (a-2)^2 \ge 0
Equality occurs when a =2 and \pi (2+x) = (2k+1)\frac{\pi}{2}
or x = k -\frac{3}{2} for some integer k
value of a for which the equation
4cosec2[pi(a+x)]+a2-4a=0
has real roots.....
\because \csc^2 \theta \ge 1 we have
LHS = 4 \csc^2 (\pi(a+x)) + a^2-4a \ge a^2-4a+4 = (a-2)^2 \ge 0
Equality occurs when a =2 and \pi (2+x) = (2k+1)\frac{\pi}{2}
or x = k -\frac{3}{2} for some integer k