for cos (log x) to exist. xmust be betn 0 and ∩/2.
taking that condn log x in that region is very close to 0. so cos(logx) is very close to 1.as cosine graph decreases from 1 to 0the interval 0-∩/2.
cos x in the region is betn0-1.so log(cos x) is negative in the region as log of something betn 0 and 1 with base>1 is negative
so cos(log x)>log(cos x)