smallest positive value of A= 105°
smallest positive values of B=45°
OR
smallest positive value of A= 45°
smallest positive values of B=105°
If cos(A-B)=1/2 and sin(A+B)=1/2 ,find the smallest positive values of A and B and also their most general values .
smallest positive value of A= 105°
smallest positive values of B=45°
OR
smallest positive value of A= 45°
smallest positive values of B=105°
plz explain how u got the ans
i am getting the general values of A and B as:
A = (n+m2)Π±Π6 + (-1)mΠ12
B = (-n+m2)Π±Π6 + (-1)mΠ12
(where n and m are integers)
now do i have to use hit and trial for values of m and n ??????
A-B=60° or -60°
A+B=150° OR 30°
FOR A+B=30° AND A-B=60°
B= -15° WHICH IS LESS THAN 0.
SO WE PUT
A+B=150° AND A-B=60°
here we get A=105° AND B=45°
PUTTING A+B=150° AND A-B=-60°
WE GET A=45° AND B=105°
SO, I GUESS ITS CORRECT! HOWEVER USE THIS FOR COMP EXMS ONLY!!