1 Answers
Manish Shankar
·Jan 16 at 5:05
(1-cos2x2)4+(1+cos2x2)4=17/32
(1-cos2x)4+(1+cos2x)4=17/2
2(1+6cos22x+cos42x)=17/2
4+24cos22x+4cos42x=17
4cos42x+24cos2x+13=0
4cos42x+26cos2x-2cos2x+13=0
(2cos22x+13)(2cos22x-1)=0
proceed from here