32tan8θ=2cos2α+3cosα
3cos2θ=1
find the general solution for α.
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1 Answers
Manish Shankar
·2014-01-16 05:30:22
cos2θ=1/3
2cos2θ-1=1/3
cos2θ=2/3
sec2θ=3/2
tan2θ=1/2
so the equation is
2=2cos2α+3cosα
proceed from here