putting n=k=1 does not satisfy.
\hspace{-16}$Prove that If $\mathbf{n}$ is an positive Integer Then,\\\\ $\mathbf{\sum_{k=1}^{n}\cos^4\left(\frac{k\pi}{2n+1}\right)=\frac{6n-5}{16}}$
thanks guys now i have edited it
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\hspace{-16}$Prove that If $\mathbf{n}$ is an positive Integer Then,\\\\ $\mathbf{\sum_{k=1}^{n}\cos^4\left(\frac{k\pi}{2n+1}\right)=\frac{6n-5}{16}}$
thanks guys now i have edited it