sin @ = k sin (# + @)
=> sin@ = k sin @ cos# + kcos@ sin#
=> sin@ - k sin@cos # = kcos@ sin#
=> sin@ (1 - k cos #) = k cos @ sin#
=> tan@ =( k sin # )/ (1-k cos#)
now use tan (@+#) = ( tan @ + tan # )/( 1-tan@ tan#).............u will get RHS
1 Answers
sakshi pandey pandey
·2009-12-14 06:17:34