trigos

if -1<x<0 den sin-1 x =?

a dice is rolled 4 times d probability of getting a larger no dan d previous no each time is?

13 Answers

1
kamalendu ghosh ·

i hope u mean sin-1x

1
kamalendu ghosh ·

-pi/2<sin-1x<0

11
virang1 Jhaveri ·

(∩/2, ∩)

11
virang1 Jhaveri ·

Total no. of possibilities = 64
if first is 1 then the no. of ways of getting a larger no dan d previous no each time i 5*4*3 = 60 ways
If first is 2 then then the no. of ways of getting a larger no dan d previous no each time is = 4*3*2 = 24
If first is 3 then then the no. of ways of getting a larger no dan d previous no each time is = 3*2*1 = 6
If first is 4 or 5 or 6 There is no possibility

Therefore the probability is 90/6*6*6*6 = 0.0694 = 0.069

24
eureka123 ·

Q1
learn the graphs dear....it will surely help u

11
virang1 Jhaveri ·

Both the answers are rite it is the way thing in a different manner

24
eureka123 ·

no dude in inverse functions.......u got to know principal domain....

ur answer (pi/2,pi) isn't in principal domain of sin-1x

i hope u get the point...

11
virang1 Jhaveri ·

ohhhhhhhhh yes thx

24
eureka123 ·

[1]

9
Celestine preetham ·

dice q

4 throws
chose any 4 nos and they can be in asc order in only one way
so fav case = 6C4

total case = 64

so probability = 15/64 =5/432

1
jb6098 swathi ·

frnds im not asking about domain but im asking weder it is Cos-1 √1-x2

or ∩-Cos-1 √1-x2

plz tell me

1
jb6098 swathi ·

frnds im not asking about domain but im asking weder it is Cos-1 √1-x2

or ∩-Cos-1 √1-x2

plz tell me

62
Lokesh Verma ·

hmm.. you can think it like this

sin -1x will be -ve

also it will be in -pi/2 to 0

so cos inverse should also be -ve

but π-Cos-1 √1-x2

will be +ve and greater than zero....

so what should you try to do?

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