7n=4?
\hspace{-16}\mathbb{I}$f $\bf{n \; \mathbb{\in \mathbb{N}}}$. Then find value of $\bf{n}$ in \\\\ $\bf{\tan^{-1}\left(\frac{1}{11}\right)+n.\tan^{-1}\left(\frac{1}{7}\right)=\tan^{-1}\left(\frac{1}{n}\right)}$
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1708Sorry friends actually there is a typo mistake...
\hspace{-16}\mathbb{I}$f $\bf{n \; \mathbb{\in \mathbb{N}}}$. Then find value of $\bf{n}$ in \\\\ $\bf{\tan^{-1}\left(\frac{n}{11}\right)+n.\tan^{-1}\left(\frac{1}{7}\right)=\tan^{-1}\left(\frac{1}{n}\right)}$
