simply apply 'componendo- devidendo' and get the result after simplifying a bit
If cosθ=ncos(θ+2α)then show that (n+1)tan(θ+α)=(n-1)cotα
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1 Answers
Amartya Kumar Mistry
·2014-06-23 03:07:35
If cosθ=ncos(θ+2α)then show that (n+1)tan(θ+α)=(n-1)cotα
simply apply 'componendo- devidendo' and get the result after simplifying a bit