1I didn't get you.
Q : A,B,C are 3 angles of a triangle. A=Ï€/4 , tanB . tanC = p.
find all possible values of p.
my approach.
B+C= 3Ï€/4
so , tanB . tan(3Ï€/4 - B) = p.
tanB=x ,
x2 + x(1-p) + p =0 .
for real roots.
Δ≥0.
so , p2 -6p +1 ≥0
which implies p ≥3 + √8 , or p ≤ 3 - √8
but here in this book ,well the approach is different ,I'll give it later. we've got p < 0 , or p ≥ (√2 + 1 )2
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9 Answers
62there's a caveat attached... the angle goes from pi/4 to pi only
so u will have to remove the other values of p :)
just see if that gives u the solution
62angle B
i guess that was a mistake i tshould have been pi/4 to 3pi/4
1then what happns? please xplain more . I'm dud in math . Better give your soln. atleast halfway.
62ok.. ok..
dont worry i will try to explain :)
I generally dont like giving the whole solution because i think that it inhibits the thinking process going in ur mind...
11Hey srinath.. u are missing somthing.. I understand what nishant is trying to say..
It is not very tough.. i cant explain.. but i have got what nishant is trying to say.. just try one time.