-
*Image* ...
-
*Image* ...
-
*Image* ...
-
A point moves with uniform acceleration and v1,v2,v3 denote the average velocities in the 3 successive time intervals of time t1,t2,t3 . which of the following is true ? a)(v1-v2):(v2-v3)=(t1-t2):(t2+t3) b)(v1-v2):(v2-v3)=(t1 ...
-
A cannon ball is fired with a velocity v is an direction making an angle θ with the horizontal. At the highest point of its path it breaks into 2 parts of equal masses.One of the parts retraces the initial path of the ball.T ...
-
*Image* ...
-
*Image* ...
-
*Image* ...
-
*Image* ...
-
*Image* ...
-
*Image* ...
-
*Image* ...
-
Assertion: In series combination, charges on two capacitors are always equal. Reason: If charges are same, the total potential difference applied across two capacitors will be distributed in inverse ratio of capacities. ...
-
If tan(inverse)(x+2/x)-tan(inverse)4/x-tan(inverse)(x-2/x)=0 then x=............ y=........... (M.L.Khanna Page 464 Problem No.37a) ...
-
1 + 1+2/1! + 1+2+3/2! + 1+2+3+4/3! + ..... ∞ = (a) 0 (b) 1 (c) 7e/2 (d) 2e Brahmastra - Exponential and logarithmic series Q No.5 ...
-
A cylindrical pulley of mass M and radius R is connected to another pulley of mass M/2 ,R/2 through a massless string as shown. If sufficient string is wrapped over larger pulley,find the accleration of mass M attached to the ...
-
A rod OA of mass m and length L hinged at end O can rotate smoothly in vertical plane about horzontal axis passing through O .It is released from a horizontal position as shown. and strikes a block of mass M kept vertically b ...
-
...
-
1. *Image* 2. *Image* 3. *Image* 4. *Image* 5. *Image* 6. *Image* ...
-
the positive values of a for which the equation [x+a]=sin(Ï€x/2) will have no solution is,where [.] denotes greatest integer function- a) (0,1); b)(1,2);c) (0,2);d) NOT. ...
-
Q1: *Image* a)-1 b)loge1 c)1 d)none q2: *Image* a) 1/2 sin3a b) 1/2 cosec2a c)sin3a d)cosec3a q3: *Image* a)1 b)-1 c)0 d)none q4:if 0<x<y then *Image* a)e b)x c)y d)none q5: *Image* a)1 b) sinx/x c) x/sinx d)none ...
-
\lim_{x\rightarrow \infty} 100[((x+1)(x+2)...(x+100))^{1/100} - x] ...
-
*Image* ...