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AIEEE Exam Results Candidates can also subscribe at http://www.btechalerts.in/ and after that soon as the AIEEE result 2012 will be declare we will inform you quickly. Candidates can also check their AIEEE 2012 result at give ...
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what rank will i get with a marks of 110? can anyone tell? ...
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Well ,the title is obvious. Any thing to share. Personally, I feel that this year's paper was DIFFICULT than the Previous years one. The questions which were doable were lenghtly (not all I mean) and some were really outsmart ...
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Well ,the title is obvious. Any thing to share. Personally, I feel that this year's paper was DIFFICULT than the Previous years one. The questions which were doable were lenghtly (not all I mean) and some were really outsmart ...
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∫03 (x2+1)d([x]). [.]→ G.I.F. ...
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given a line with its equation ax + by + c = 0 suppose we rotate the co-ordinate axis with an angle of 78°, what will happen to the eqn. of the line? ...
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What are the forces acting on the ladder in the example below *Image* The ladder is held against the wall, the wall is friction-less. So what will be the fores acting on the ladder? please help...........!! ...
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has anyone got the results yet? ...
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has anyone got the results yet? ...
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1) \lim_{x\rightarrow \frac{\pi }{2}} sec^{-1}(sin x) 2) \lim_{x\rightarrow 0}cos\frac{1}{x} 3) \lim_{x\rightarrow 0}(1+sinx)^{1/x^{2}} 4) Let f( x+y/2 ) = f(x)+f(y)/2 for all real x and y.If f'(0) = -1 and f(0) = 1,find f(2) ...
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1) \lim_{x\rightarrow \frac{\pi }{2}} sec^{-1}(sin x) 2) \lim_{x\rightarrow 0}cos\frac{1}{x} 3) \lim_{x\rightarrow 0}(1+sinx)^{1/x^{2}} 4) Let f( x+y/2 ) = f(x)+f(y)/2 for all real x and y.If f'(0) = -1 and f(0) = 1,find f(2) ...
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has anyone got the results yet? ...
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*Image* show the product with mechanism please. ...
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Can anyone explain to me what is ortho effect? ...
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1) \lim_{x\rightarrow \frac{\pi }{2}} sec^{-1}(sin x) 2) \lim_{x\rightarrow 0}cos\frac{1}{x} 3) \lim_{x\rightarrow 0}(1+sinx)^{1/x^{2}} 4) Let f( x+y/2 ) = f(x)+f(y)/2 for all real x and y.If f'(0) = -1 and f(0) = 1,find f(2) ...
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prove that [√(4n+1)]=[√n+√(n+1)] for n belonging to positive integers. [.]→ G.I.F ...
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f(x) is a real valued function satisfying f(x-y)=f(x)f(y)-f(a-x)f(a+x) f(0)=1 then f(2a-x) is a) f(-x) b) f(x) c(-f(x) d f(a) +f(a-x) ...
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prove that [√(4n+1)]=[√n+√(n+1)] for n belonging to positive integers. [.]→ G.I.F ...
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f(x) is an invertible function and f(x)=xsin x ; g(x)=f -1(x). find the area bounded by y=f(x) and y=g(x). ...
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f(x) is an invertible function and f(x)=xsin x ; g(x)=f -1(x). find the area bounded by y=f(x) and y=g(x). ...
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P (5,3) . R lies on y=x and Q lies on x axis. what is the co-ordinate of Q so that PR+PQ+QR is minimum? ...
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Q: Why is easier to break a piece of paper that you wet dry? ...
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\hspace{-16}\mathbf{(1)\;\; \int\frac{1}{x+\sqrt{x^2+x+1}}dx}$\\\\\\ $\mathbf{(2)\;\; \int\frac{\sqrt{\sqrt{x^4+1}-x^2}}{x^4+1}dx}$ ...
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\hspace{-16}\mathbf{(1)\;\; \int\frac{1}{x+\sqrt{x^2+x+1}}dx}$\\\\\\ $\mathbf{(2)\;\; \int\frac{\sqrt{\sqrt{x^4+1}-x^2}}{x^4+1}dx}$ ...
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\hspace{-16}\mathbf{(1)\;\; \int\frac{1}{x+\sqrt{x^2+x+1}}dx}$\\\\\\ $\mathbf{(2)\;\; \int\frac{\sqrt{\sqrt{x^4+1}-x^2}}{x^4+1}dx}$ ...
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*Image* *Image* ...
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Evaluate: ∫01 xa-1/ln x dx ...
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*Image* *Image* ...
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*Image* *Image* ...
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*Image* *Image* ...
