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A compilation of quesitons similar to the way bhargav had one :P (hence borrowed a part of the name..) Keep solving and i will keep adding questions here... To begin with first 5 are here... Question 1) \left(\frac{dy}{dx}+1\ ...
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A compilation of quesitons similar to the way bhargav had one :P (hence borrowed a part of the name..) Keep solving and i will keep adding questions here... To begin with first 5 are here... Question 1) \left(\frac{dy}{dx}+1\ ...
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1..if f:R→R be a differential finction such that that f(2-x)=f(x) and f(5-x)=f(5+x) then 1.f'(-3)=0 2..f'(9)=0 . 3.if \int_{3}^{5}{f(x)dx=k},then \int_{11}^{15}{f(x) dx} wil l be k ...
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Prove that (\sin \gamma + a \cos \gamma)(\sin \gamma + b \cos \gamma) \le 1 + \left( \frac{a+b}{2} \right)^2 for reals a,b ...
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For a,b,c belonging in R+ the minimum value of (a+3c)/(a+2b+c)+4b/(a+b+2c)-8c/(a+b+3c) A)12+17√2 B)-12+17√2 C)-17+12√2 D)17-12√2......... ...
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1..IF P,Q,R MAY BE PERIMETER ,CIRCUMRADIUS AND INRADIUS OF AN ARBITARY TRIANGLE THE WHICH OF THE FOLLOWING MAY NOT BE ALWAYS TRUE-- (A)P>Q+R (B) P≤Q+R (C)P/6<Q+R<6P (MULTI ANSWER) ...
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evaluate !!!!!!!!!!!!!! 1. \int \frac{3x ^2 - 7 dx}{ (x^2 -4) ( x^2 + 1 ) } 2 . \int \frac{ dx}{ x.\sqrt{x^6 + 1} } 3. \int \frac{ \sqrt{x} dx}{(1+ x^2)^{\frac{7}{4}}} just practice problems [1] ...
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1..IF P,Q,R MAY BE PERIMETER ,CIRCUMRADIUS AND INRADIUS OF AN ARBITARY TRIANGLE THE WHICH OF THE FOLLOWING MAY NOT BE ALWAYS TRUE-- (A)P>Q+R (B) P≤Q+R (C)P/6<Q+R<6P (MULTI ANSWER) ...
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ses x - cos x = K1 cosec x- sin x = k2 the eliminant of x between the equation is a) ( K22*K1)2/3 + (K2*K12)2/3 =1 b) K22 + K12/K22 = 2 c) K12/3*K22/3(k12/3 + K22/3) = 1 d) K1*K22 + k2*K12 = 2 ...
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The circles on focal radii of a parabola as diameter touch A The tangent at the vertex B The axis C The directrix D None of above ...
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For a,b,c belonging in R+ the minimum value of (a+3c)/(a+2b+c)+4b/(a+b+2c)-8c/(a+b+3c) A)12+17√2 B)-12+17√2 C)-17+12√2 D)17-12√2......... ...
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limx→π/2 (sinx - sinxsinx)/(1-sinx+lnsinx) ...
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limx→π/2 (sinx - sinxsinx)/(1-sinx+lnsinx) ...
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limx→π/2 (sinx - sinxsinx)/(1-sinx+lnsinx) ...
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limx→π/2 (sinx - sinxsinx)/(1-sinx+lnsinx) ...
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*Image* correct ans b Post the solution..... ...
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Good Obj. Qn(s)... Needed to clarify & verify my answers, 'coz i don't have the list of correct ones. SINGLE ANSWER CORRECT *Image* *Image* MULTIPLE ANSWERS CORRECT *Image* Do post the answers u all got. ...