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a light of wavelength λ is incident on a metal sheet of work function 2ev. The wavelength I varies with time as I=3000+40t., where I is in A and t is in sec.The power incident on the metal surface is 100W. the signal is swit ...
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a light of wavelength λ is incident on a metal sheet of work function 2ev. The wavelength I varies with time as I=3000+40t., where I is in A and t is in sec.The power incident on the metal surface is 100W. the signal is swit ...
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happy birthday ! ...
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THIS THE CLUB OF NON VALENTINES LONELY ONES R INVITED register by writing ur name with a * 1. vishal* ...
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hiii...ma frndz...here m wid..... these r sum interisting information abt 'numbers'...jst watch out... d greatest no. one can make by 3 digit is 99^9 !! it can b shown dat dis no. has abt 369693100 digits.assuming there can b ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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If α and β are roots of z +1/z =2(cosθ+isinθ) ,0<θ<π then show that mod(α-i)=mod(β-1) ...
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a straight line through a (-5,-4) meets the lines x+3y+2=0,2x+y+4=0 and x-y-5=0 at b,c,d respectively.......... if (15/ab)^2+(10/ac)^2=(6/ad)^2 then the equationof the straight line?? ...
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a straight line through a (-5,-4) meets the lines x+3y+2=0,2x+y+4=0 and x-y-5=0 at b,c,d respectively.......... if (15/ab)^2+(10/ac)^2=(6/ad)^2 then the equationof the straight line?? ...
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if I = 0∫1 dx/ [(5+2x-2x2)(1+ e2-4x)] and, I1 = 0∫1 dx/ (5+2x-2x2) , then... a) I = I1 b) I = 2 I1 c) 3I = 5 I1 d) not. ...
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if I = 0∫1 dx/ [(5+2x-2x2)(1+ e2-4x)] and, I1 = 0∫1 dx/ (5+2x-2x2) , then... a) I = I1 b) I = 2 I1 c) 3I = 5 I1 d) not. ...
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if I = 0∫1 dx/ [(5+2x-2x2)(1+ e2-4x)] and, I1 = 0∫1 dx/ (5+2x-2x2) , then... a) I = I1 b) I = 2 I1 c) 3I = 5 I1 d) not. ...
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if I = 0∫1 dx/ [(5+2x-2x2)(1+ e2-4x)] and, I1 = 0∫1 dx/ (5+2x-2x2) , then... a) I = I1 b) I = 2 I1 c) 3I = 5 I1 d) not. ...
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if I = 0∫1 dx/ [(5+2x-2x2)(1+ e2-4x)] and, I1 = 0∫1 dx/ (5+2x-2x2) , then... a) I = I1 b) I = 2 I1 c) 3I = 5 I1 d) not. ...
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There will be only one test for each remaining phase and duration of taking the test is also increased. New dates for phase tests: Phase Dates Results Phase3: 10th Jan-18th Jan 19th Jan Phase4: 24th Jan-1st Feb 2nd Feb Phase5 ...
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*Image* the cells given in the circuit are 5v each and have internal resistance of 0.2 ohms, then the reading in the ideal volt meter is?? ...
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*Image* the cells given in the circuit are 5v each and have internal resistance of 0.2 ohms, then the reading in the ideal volt meter is?? ...
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*Image* the cells given in the circuit are 5v each and have internal resistance of 0.2 ohms, then the reading in the ideal volt meter is?? ...
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*Image* the cells given in the circuit are 5v each and have internal resistance of 0.2 ohms, then the reading in the ideal volt meter is?? ...
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*Image* the cells given in the circuit are 5v each and have internal resistance of 0.2 ohms, then the reading in the ideal volt meter is?? ...
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Dear aspirants, The First Part-Test starts today & will continue till 9th December. You can take this test anytime during this period. The Link for taking this test will be put up on your homepage very shortly, keep looking a ...
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If the number of even divisors of 4320 is M then the number of primes less than or equal to M is?? ...
