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  0.1 millimole of CdSO4 is present in 10mL acid solution of 0.08 N HCl.Now H2S is passed to ppt. all the Cd2+ ions.The pH of the soln after filtering off ppt,boiling off H2S and making the solution 100 mL by adding water is ap ...
  0·6· #Chemistry#Inorganic Chemistry
  commented2015-12-13 12:35:26