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if tan(πcosθ)=cot(πsinθ) then form eqn whose roots are cosθ and sinθ ...
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if tan(πcosθ)=cot(πsinθ) then form eqn whose roots are cosθ and sinθ ...
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\boxed{1} Find the value of a for which \int_{0}^{\pi}\{ax(\pi^{2}-x^{2})-\sin x\}^{2}dx is minimized. (easy one) for prac. \boxed{2} Let f(x) be a continuous function satisfying *Image* Find the value of k for which *Image* ...
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1. Statement-1: In diamond carbon atoms occupy alternate tetrahedral voids in the FCC lattice formed by the carbon atoms Statement-2: In diamond, packing fraction ismore than 74%. 2. Which of the following properties of theme ...
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DO U KNOW THAT WORLD'S LARGET KNOWN PRIME NUMBER IS \left( 2^\left( 13466917\right)\right)-1 ...
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If CO Bond length = 1.128 Angstorm, then the possible value of CO bond length is Fe(CO) is (a) 1.128 A (b) 1.10A (c) 1.13 A (d) 10115A I do not understand how the d pi- p pi bonding will affect eh bond order of CO bond….??? ...
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If CO Bond length = 1.128 Angstorm, then the possible value of CO bond length is Fe(CO) is (a) 1.128 A (b) 1.10A (c) 1.13 A (d) 10115A I do not understand how the d pi- p pi bonding will affect eh bond order of CO bond….??? ...
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If CO Bond length = 1.128 Angstorm, then the possible value of CO bond length is Fe(CO) is (a) 1.128 A (b) 1.10A (c) 1.13 A (d) 10115A I do not understand how the d pi- p pi bonding will affect eh bond order of CO bond….??? ...
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find *Image* ...
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find *Image* ...
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find *Image* ...
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*Image* please solve above two questions. ...
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*Image* please solve above two questions. ...
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A:B/w SiCl4 and CCl4 ,only SiCl4 reacts with water. R:SiCl4 is ionic and CCl4 is covalent ...
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1. \int \frac{x^2}{\sqrt{1- x^2}} 2. \int \frac{x^3}{\sqrt{1- x^2}} 3 . \int \frac{dx}{( x^2 + 1 ) ^2 } = \frac{A}{148}\tan^{-1} x +\frac{x}{2(x^2 + 1)} find value of A 4 . \int \frac{(1+ logx )dx}{\sqrt{x^{2x}-1}} for practi ...
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IF ∫(sin 3θ + sin θ)esin θ cos θ dθ = (Asin 3θ + Bcos 2θ + Csin θ + D cos θ + E)esin θ + c find A, B , C , D , E ANS---> -4 , -12 , -20 , 0 , 32 respectively ...
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Find the no. of ways of arranging 5 identical green, 4 identical blue and 3 identical yellow balls in a row such that none of the identical balls form a block (or in other words...comes serially :-). ...
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Find no of solutions of : Sin(pi x)=|log|x||. ...
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TODAY IS THE BIRTHDAY OF NISHANT SIR SO WISH HIM HAPPY BIRTHDAY ...
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Q 1 -Find the electric field a distance z above the center of a square loop (side a) that has charge density sigma. Q-2 -Two spheres, each of radius R and carrying uniform charge densities +p and —p, respectively, are place ...
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anyone received it ????????????????? ...
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Guys do u feel BT aits are getting tougher that FIITJEE even??????????????????wat i want to know is ......i jus got the STimulator tests ( YELLOW BOOK) ...the tests in them are easier ..........bit are they of JEE LEVEL...... ...
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Show that (n2)! is divisible by (n!)^n ...
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Here's a problem that I found out in an olympiad book......and I really enjoyed solving it. The question is : Find the sum of the given expression : [ n+1/2 ] + [ n+2/22 ] + [ n+22/23 ] + ................ + [ n+2k/2k+1 ] wher ...
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Find the no. of ways of arranging 5 identical green, 4 identical blue and 3 identical yellow balls in a row such that none of the identical balls form a block (or in other words...comes serially :-). ...
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\texttt{The number of natural numbers between 1 to 2000 such that sum of digits of their sqaures is eqaul to 21} ...
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IF ∫(sin 3θ + sin θ)esin θ cos θ dθ = (Asin 3θ + Bcos 2θ + Csin θ + D cos θ + E)esin θ + c find A, B , C , D , E ANS---> -4 , -12 , -20 , 0 , 32 respectively ...
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Here's a problem that I found out in an olympiad book......and I really enjoyed solving it. The question is : Find the sum of the given expression : [ n+1/2 ] + [ n+2/22 ] + [ n+22/23 ] + ................ + [ n+2k/2k+1 ] wher ...
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\int \frac{\sqrt{x}dx }{1- x} another for practice 2. \int_{0}^{\frac{\pi }{2}}{ \frac{sinx cosx dx }{ cos^2x + 3cosx + 2}} ...
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Find the no. of ways of arranging 5 identical green, 4 identical blue and 3 identical yellow balls in a row such that none of the identical balls form a block (or in other words...comes serially :-). ...
