Mihir Khare
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BITSAT 2015 Discussion Forum
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Mihir Khare
Recently Commented Questions
Identities.
A+B+C=180 degree. Prove that, 1)sin(B+2C) + sin (C+2A) + sin(A+2B) = 4sin(B-C)/2* sin(C-A)/2 *sin(A-B)/2 2) (sin2A+sin2B+sin2C)/(sinA+sinB+sinC) = 8*sin(A/2)*sin(B/2)*sin(C/2) 3)sin(B+C-A) + sin(C+A-B) + sin(A+B-C) =4sinAsinB
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7
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#Mathematics
#Trignometry
commented
2017-03-09 09:27:31
remainder
find the remainder when 2740 is divided by 12
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5
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#Mathematics
#Algebra
commented
2017-02-18 23:15:14
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