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How do we separate ethane from monochloroethane physically... like in a reactor? The given situation is that monochloroethane is being produced by chlorination of ethane.. i want more of product.. so i am applying le chatteli ...
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re^{-r/2}cos\theta =constant where r is the radial distance of the point from origin and theta is the colatitude (angle btw the radial vector and the one pointing towards the z coordinate of the point)) ...
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consider a plane progressive wave y=A sin(kx-wt) propagating in a string having tension F. What is the linear impulse given by the F-transverse acting at x=0 on the time interval t=0 to t= T/4? (asumptions tanθ≈sinθ; Ampl ...
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FIND cos(3x) - sin(3x) IF cos(2x) - cosx = sin(4x) - sinx AND tanx is not 1!!! ...
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kinetic energy of a system cannot be increased without applying any external force on the system. true or false????????? its given to be false????? how can this be????? ...
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find the point inside the triangle ABC so that the largest distance from any side is minimum. a) centroid b) orthocenter c) circumcentre d) none of these ...
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let f(X) be a continous funtion such that f(x)>0 and f(x)^101 =1+∫ f(t)dt.[integrate from 0 to x] the value of (f(100))^101 a) 99 b) 100 c) 101 d) 98 ...
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express (2^(1/3)-1)^(1/3) in the form of a,b,c (use only + or - btw a,b,c) where a= (1/9)^ (1/3), b= (2/9)^ (1/3), c= (4/9)^ (1/3) ...
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cosnθ = [P][/n] (cosθ) [P][/n] is a polynomial of degree n like [P][/2] = 2x^{2}-1 (n is a natural no.) then find (x+\sqrt{x^{2}-1})^{n} +(x-\sqrt{x^{2}-1})^{n} in terms of [P][/n] ...
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find \int_{0}^{\pi/4}{\frac{x dx}{cosx(cosx +sinx)}} ...
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when Fe(s) is dissolved in aq HCl in a closed vessel, the work done is? positive,negative or 0?? and why? ...
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i know this is not directly integrable, bt i'm nt getting any way to directly derive this relationship if \int_{0}^{1}{\frac{e^{t}}{t+1}} =a and \int_{3}^{4}{\frac{e^{t}}{t-5}} =b then find the relation btw a and b??? ...
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Find all real values of the parameter a for which the equation (a-1)z^{4}-4z^{2} +a+2=0 has only pure imaginary roots. ...