-
1) find the value of : 4cos20 - √3 cot20 2) 2cos40 - cos20/sin20 ...
-
1) tan9 - tan27- tan63 + tan81 =4 2) sin4 π/6 + sin4 3π/6 +sin4 5π/6 + sin4 7π/6 = 3/2 3)find the value of : 4cos20 - √3 cot20 4) find the value of : 2√2 sin10 [ sec 5/2 + cos 40/ cos5 - 2sin35] 5)sin212 + sin221 + si ...
-
1) tan9 - tan27- tan63 + tan81 =4 2) sin4 π/6 + sin4 3π/6 +sin4 5π/6 + sin4 7π/6 = 3/2 3)find the value of : 4cos20 - √3 cot20 4) find the value of : 2√2 sin10 [ sec 5/2 + cos 40/ cos5 - 2sin35] 5)sin212 + sin221 + si ...
-
1.find the number of ways in which m boys and n girls may be arranged in a row so that no two girls are together . given that m>n 2. In an exam,10 candidates have to appear. 4 candidates are to appear in maths and rest in ...
-
PROVE: n!/r! (n-r)! + n!/(r-1)!(n-r+1)! = (n+1)!/r! (n-r+1)! ...
-
find the consecutive terms in the binomial expansion of (3+2x)^7 whose coefficients are equal.. ...