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More is the hydration enthalpy of an ion, more vigorously will it dissolve in water. Why is it so? ...
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6x+5y=7x+3y+1=2(x+6y-1) AND x+y-8/2 = x+2y-14/3 = 3x+y-12/11 ...
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find the eqn. of those tangents to the circle x2 + y2 - 2x - 4y - 4 = 0 which are parallel to the line 3x - 4y - 1 = 0 ...
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A line is drawn through a fixed point P (m,n) to the circle x2 + y2 = r2 at A and B. Find PA x PB. ...
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there is a isosceles triangle inside a parabola y2=x, with one vertex (0,0), than find the length of the sides of triangle ...
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A circle along with one of its diameter AB are given.There lies a point P in the plane.Construct the perpendicular to AB through P using only a ruler.(A ruler can only connect 2 points). ...
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x1, x2, x3 are in GP and y1, y2,y3 are also in GP with same common ratio. then (x1,y1), (x2,y2)&(x3,y3) these are a]vertices of a triangle b]situated on a circle c]collinear d]situated on an ellipse ...
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Arrange the following in increasing order of dehydration *Image* ...
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if D = diag(a1 , a2 , a3 , ...... an), where ai ≠0 for all i = 1,2....,n, then show that D-1 = diag(a1-1 , a2-1 , a3-1 , .......... an-1). ...
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Two rods of different materials with coefficients of linear expansion α1 and α2 respectively; Young's moduli Y1 & Y2 respectively; of initial lengths l1 and l2 respectively are joined at one end. the free ends are fixed to ...
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How do I prove sin2A-sin2B=sin(A+B)sin(A-B) ? ...
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sin a+cos b=2/3 sin b+cos a=1/3 Find tan((a-b)/2)? Note:Please give the shortest method....I know the longer one... ...
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please remove this new look.... i think this has resulted in loss of users from targetIIT.... some demerits i feel are... 1. we can't see recent posts... 2. neither an option for latex 3. looks so bad.. 4. a bit complex to us ...
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integration of x^2/(a+bx)^2. ...
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What is the value of tan-1((1/2)tan2A)+ tan-1(cotA)+ tan-1(cot3A) ? ...
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If P(x) is a polynomial such that P(x2+1)={P(x)}2+1 and P(0)=0,then ∂P/∂x is equal to: (a)-1 (b)0 (c)1 (d)none of these ...
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\hspace{-16}$If $\bf{f:\mathbb{Z}\rightarrow \mathbb{Z}}$ and $\bf{m + f\big(m + f(n + f(m))\big) = n + f(m)}$\\\\ and $\bf{f(6)=6}$.\;Then $\bf{f(2012)=}$ ...
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\hspace{-16}$If $\bf{f:\mathbb{Z}\rightarrow \mathbb{Z}}$ and $\bf{m + f\big(m + f(n + f(m))\big) = n + f(m)}$\\\\ and $\bf{f(6)=6}$.\;Then $\bf{f(2012)=}$ ...
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value of f(0), so that its function f(x)=( 1+2x - 1+2x )/x is continues is a)1/3 b)3 c)-1/3 d)0 ...
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If f(x)=[x2]-[x]2 and x lies between [0,2] then the range of f(x) is: (a){-1,0} (b){-1,0,1} (c){0} (d){0,1,2} ...
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sin ax+cos ax and |sin x|+|cos x| are periodic functions of same fundamental period then a is: (a)0 (b)1 (c)2 (d)4 ...
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\hspace{-16}$The Minimum value of the Expression \\\\\\ $\bf{\sqrt{(x_{1}-x_{2})^2+\left(\frac{x^2_{1}}{20}-\sqrt{(17-x_{2})\times (x_{2}-13)}\right)^2}}$\\\\\\ Where $\bf{x_{1}\in \mathbb{R^{+}}}$ and $\bf{x_{2}\in (13,17)}$ ...
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The condition that the chord x cos A+y sin A-p=0 of x2+y2-a2=0 may subtend a right angle at the center of the circle is: (a)a2=2p2 (b)p2=2a2 (c)a=2p (d)p=2a ...
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\hspace{-16}$Find real values of $\bf{x}$ in $\bf{ {5}^{1+x}+{5}^{1-x}={2}^{1+x}+{2}^{1-x}+{3}^{1+x}+{3}^{1-x}}$ ...
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\hspace{-16}$Find Range of $\bf{f(x)=\frac{\sin^{-1}(x)}{2}+\frac{\cos^{-1}(x)}{3}+\frac{\tan^{-1}(x)}{4}}$ ...
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cosider these two reactions, *Image* My question is why in the case of chlorination the major product formed is different than the one formed in the bromination..? ...
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cosider these two reactions, *Image* My question is why in the case of chlorination the major product formed is different than the one formed in the bromination..? ...
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suppose f:R->R is a differentiable function and f(1) = 4, then find the value of lim ∫(frm 0 to 4){ 2t/x-1 dt}. x->1 ...
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let, f( x+y/2 ) = f(x)+f(y)/2 for all real x and y and f'(0) exists and equals -1 and f(0) = 1, find f(2) ...
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find domain of sin-1 { x2 + 1/2x } m not able to find it... please help me...!! ...
