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1. lim na sin2n!/n+1 n→∞ a E (0,1) is equal to (a) 0 (b) 1 (c) ∞ (d) does not exist 2.lim {11/sin2x + 21/sin2x+....+n1/sin2x}sin2x x→0 3. lim xn+nxn-1+1/e[x] x→∞ ...
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Area bounded by the curve y=ex2, x-axis and the lines x=1, x=2 is given to be equal to a sq units. Area bounded by the curve y=√(ln x) , y-axius, and the lines y=e and y=e4 is equal to ? ...
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Area bounded by the curve y=ex2, x-axis and the lines x=1, x=2 is given to be equal to a sq units. Area bounded by the curve y=√(ln x) , y-axius, and the lines y=e and y=e4 is equal to ? ...
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how many of u r giving fiitjee aits part test 1 on 25th??? ...
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Does any body know the "Extra Force Method" to solve the spring pulley system. And also I want to know if there is any other method to solve pulley problems(system containing a no of pulleys). if yes then plz tell me..... ...
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Does any body know the "Extra Force Method" to solve the spring pulley system. And also I want to know if there is any other method to solve pulley problems(system containing a no of pulleys). if yes then plz tell me..... ...
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if f(x)=loge x and g(x)=x2 and 4<c<5 then c log (425/516) is equal to (a) c loge5 - 8 (b) 2(c2 loge4 - 8) (c) 2(c2 loge5 - 8) (d) c loge4 - 8 ...
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if f(x)=loge x and g(x)=x2 and 4<c<5 then c log (425/516) is equal to (a) c loge5 - 8 (b) 2(c2 loge4 - 8) (c) 2(c2 loge5 - 8) (d) c loge4 - 8 ...
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if f(x)=loge x and g(x)=x2 and 4<c<5 then c log (425/516) is equal to (a) c loge5 - 8 (b) 2(c2 loge4 - 8) (c) 2(c2 loge5 - 8) (d) c loge4 - 8 ...
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if f(x)=loge x and g(x)=x2 and 4<c<5 then c log (425/516) is equal to (a) c loge5 - 8 (b) 2(c2 loge4 - 8) (c) 2(c2 loge5 - 8) (d) c loge4 - 8 ...
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Let h(x)=f(x)-(f(x))2+(f(x))3 for every real no x. Then- (a)h is increasing whenever f in is increasing. (b)h is increasing whenever f is decreasing. (c)h is decreasing whenever f is decreasing. (d)nothing can be said in gene ...
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The function f(x)=sin4x+cos4x increases if (a)0<x<pi/8 (b)pi/4<x<3pi/8 (c)3pi/8<x<5pi/8 (d)5pi/8<X<3pi/4 ...