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If f(x) is an invertible func such that f(x) + f(-x)=2a then ∫a-xa+x f-1(t)dt equals : ...
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The value of i log(x – i) + i2+i3 log(x +i) + i4( 2 tan-1x), x> 0 is (A) 0 (B) 1 (C) 2 (D) 3 ...
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Let f(x+y)=f(x).f(y) and f(x)=1+sin(3x).g(x) where g(x) is cont. , then f'(x) is a) f(x).g(0) b)3g(0) c) f(x).cos(3x) d)3f(x).g(0) e)3f(x).g(x) ...
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Find the accln of the block of mass M shownin the figure . The co-efficient of friction between the 2 blocks is μ1 and that between the bigger block and ground is μ2 *Image* ...
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How much volume of air will be needed for complete combustion of 10 lit. ethane? I'm getting the answer as 35 but the answer given is 175 lit. ...
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∫ x.tan x . dx ...
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Equation of the line through the point ( 1/2 ,2) and tangent to the parabola y = - x2/2 + 2 and secant to the curve y = 4 - x2 is (A) 2x + 2y - 5 = 0 (B) 2x + 2y - 3 = 0 (C) y-2 = 0 (D) None of these ...
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Equation of the line through the point ( 1/2 ,2) and tangent to the parabola y = - x2/2 + 2 and secant to the curve y = 4 - x2 is (A) 2x + 2y - 5 = 0 (B) 2x + 2y - 3 = 0 (C) y-2 = 0 (D) None of these ...
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Equation of the line through the point ( 1/2 ,2) and tangent to the parabola y = - x2/2 + 2 and secant to the curve y = 4 - x2 is (A) 2x + 2y - 5 = 0 (B) 2x + 2y - 3 = 0 (C) y-2 = 0 (D) None of these ...
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*Image* ...
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What is component of vector? Plzz explain in simple manner ...
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*Image* Thanx in advance... ...
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A small block of mass m is placed on the top of a right triangular block of mass M, which in turn is placed on a horizontal surface. All the surfaces are frictionless. Angle of inclination is α. Height of the triangular bloc ...
