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• Another limit
  Find the following limit for \alpha >1 : \lim_{n\to \infty} n\left(\dfrac{1^\alpha + 2^\alpha + \ldots + n^\alpha}{n^{\alpha+1}}-\dfrac{1}{\alpha +1}\right) Here n is a natural number. ...
  0·20· #Mathematics#Calculus
  replied2010-07-21 06:11:35