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A point P moves inside the triangle formed by A (0,0) , B(1,1/ 3 ) and C(2,0) such that min { PA,PB,PC} =1 then the area bounded by the curve traced by P is a. 3 3 +3pi/2 b. 3 3 -3pi/2 c. 3 -pi/2 d. 3 +pi/2 NOTE→Please give ...
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Lim (x→∞) 2t-3t/xn where t= xn/ex and n ε N = a.ln(2/3) b.0 c.n ln(2/3) d. not defined ...
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find ∫ x2 lnx/ 1-x2 dx lower limit =0 and upper limit = 1 ...
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find ∫ x2 lnx/ 1-x2 dx lower limit =0 and upper limit = 1 ...
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integrate log(sin 2x) dx lower limit=0 upper limit=pi/2 ...
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integrate log(sin 2x) dx lower limit=0 upper limit=pi/2 ...
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integrate log(sin 2x) dx lower limit=0 upper limit=pi/2 ...
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∫ x+ x2+2 dx = ? ...
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∫ x+ x2+2 dx = ? ...
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m,n belongs to I+ then lim x→0 sinXn/(sinX)m equals to a. 1 if n<m b. 0 if n=m c. n/m d. 0 if n>m ...
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Do the following limits exist .. limit x→0 x*sin(1/x) limit x→0 x*tan(1/x) limit x→0 tan(1/x) ...
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For what value of k does the function y= x3- 3(7-k)x2-3(9-k2)x+2 , x>0 has a point of maximum ? ...
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For what value of k does the function y= x3- 3(7-k)x2-3(9-k2)x+2 , x>0 has a point of maximum ? ...
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For what value of k does the function y= x3- 3(7-k)x2-3(9-k2)x+2 , x>0 has a point of maximum ? ...
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For what value of k does the function y= x3- 3(7-k)x2-3(9-k2)x+2 , x>0 has a point of maximum ? ...
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For what value of k does the function y= x3- 3(7-k)x2-3(9-k2)x+2 , x>0 has a point of maximum ? ...
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If f(x)= x3 + ax2 + bx +c attains its local minima at certain negative real number , then then the signs of a2-3b , a , b respectively are a. + - - b.+ - + c. + + - d. + + + ...
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If x1 and x2 are the solutions of ex2(sinx+cos x)=1/2 , where x1 ,x2≠0 , then the maximum number of the solutions of the equation ex2(sin x-cos x)=x lying between x1 and x2 can be a.2 b.0 c.1 d.none of these please give a s ...
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Do the following limits exist .. limit x→0 x*sin(1/x) limit x→0 x*tan(1/x) limit x→0 tan(1/x) ...
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Do the following limits exist .. limit x→0 x*sin(1/x) limit x→0 x*tan(1/x) limit x→0 tan(1/x) ...
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Do the following limits exist .. limit x→0 x*sin(1/x) limit x→0 x*tan(1/x) limit x→0 tan(1/x) ...
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find limit n→∞ cos(x/2) X cos(x/4) X cos(x/8)..............cos(x/2n) if f(x)= (1+2cosx)(1+2cos2x)(1+2cos4x)........(1+2cos32x) find f(2pi/13) ...
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find limit n→∞ cos(x/2) X cos(x/4) X cos(x/8)..............cos(x/2n) if f(x)= (1+2cosx)(1+2cos2x)(1+2cos4x)........(1+2cos32x) find f(2pi/13) ...
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find limit n→∞ cos(x/2) X cos(x/4) X cos(x/8)..............cos(x/2n) if f(x)= (1+2cosx)(1+2cos2x)(1+2cos4x)........(1+2cos32x) find f(2pi/13) ...
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find limit n→∞ cos(x/2) X cos(x/4) X cos(x/8)..............cos(x/2n) if f(x)= (1+2cosx)(1+2cos2x)(1+2cos4x)........(1+2cos32x) find f(2pi/13) ...
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f(x)=(sin3x + Asin2x +Bsinx) / x^5 (x is not equal to 0) is continuous at x=0. Without using L-Hospital or Series expansion, Find A and B ...
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tha dielectric constant decreases if the temperature is incresed.explain this in terms of polarisation ...
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You can put down all your complaints.. errors on tests and anything that u dont like about this site.. on this thread. I will try to make it sticky so that it is always in the home page view! Or may be link this thread to ana ...
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Many many happy returns of the day Sir. Thank you very much for all that you are doing for us! [1] ...
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x = sin2t / cos 2t y= cos2t / cos 2t find the value of the product of the cube of y and the second derivative of y wrt x ...
