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• super easy
  This functional equation is nice and has a super short and elegant solution: Find all functions f: N --> N such that xf(y) + yf(x) = (x + y)f(x2 + y2) for all x, y and in N, where N = {0, 1, 2, 3, ...}. ...
  0·13· #Mathematics#Algebra
  replied2009-07-24 08:30:36