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The value of sine of angle between the vectors 2 i - j + 3 k and 3 i + 2 j + k is

A stupid qs I know

But if i take dot product i am getting cos A = 1/2 so sin A = root 3/2

But if i take cross product i am getting sin A =1 /2

Where's the mistake ??????

4 Answers

1
rahul nair ·

ur calculation of cross prod. is wrng....sinA=√3/2

4
UTTARA ·

SRY my calc misti

Thanks

1708
man111 singh ·

(1) a,b ,c are three non zero vectors such that c is not orthogonal to b. If vector r = xi + yj +zk (whrer i,j,k are unit vectors) satisfy r *b =a*b and r.c=0. Then r*a =
(where * denote cross product).

3
rocky ·

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