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*Image* answer Q 10,11,12,14,16. ...
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*Image* answer Q no 18. ...
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*Image* Plz answer Q no 5 and 7. ...
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Let α=cis2Π/11 ,λ=α6 ,μ=α7, β=α2 1)Re(λ+λ2+λ3+λ4+λ5)= 2) (μ-β)(μ-β2).................(μ-β10)= 3)(i-β)(i-β2).................(i-β10)= answers -1/2 0 i ...
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In how many ways can 18900 be split in 2 factorrs wich are relative primes ( or coprime ) ?? Ans : 8 ...
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express in polar form 1.1 +itanA 2.tanA-i 3.1-sinA+icosA ...
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jee is on 12th and today is 10th.by now all must have finished their mathematics practice and would like to have some nice revisionary notes.so,here it is. *Image* nishant sir,should i continue posting,if you permit. if any o ...
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Reason-Assertion Type prob a)st-1 is true.st-2 is false b)st-1 is false,st-2 is true c)st-1 is true,st-2 is true,st-2 is correct explaination of st-1 d)st-1 is true,st-2 is true,st-2 is not correct explaination of st-1 Q1)St- ...
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if a=cosA+isinA,then 1+a/1-a = 1.cotA/2 2.cot A 3.icotA/2 4.itanA/2 ...
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if z=(1+2i)/{1-(1-i)2} then arg(z) is 1.0 2.pi/2 3.pi 4.none me getting 2tan-12 ...
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if z is a non-zero complex no.,then mod.[mod{(conjugate of z)2} /(z*conjugate of z)] is_______________. me getting 1. ...
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if z=-2/(1+i√3),arg(z) is- 1.pi 2.pi/3 3.2pi/3 4.pi/4 ...
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ΣΣ(r+s)(cr+cs+crcs) 0≤r ...
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2 nos. are randomly selected frm 1,2,3,..........25 Wat is the prob. that Diff. b/w First and the Second no. selected is NOT less than 10 I m getting 2/5 Ans given : 1/5 ...
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*Image* ? ...
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if roots of a quadratic equation are imaginary, then these are conjugates of each other...true/false ...
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*Image* *Image* ...
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find the number of surjections from A to B where A={1,2,3,4} and B= {a,b,c} . please explain :) ...
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How to find the sum of the following series- (1)1/1x2+1/2x3+1/3x4+...upto n terms (2)52+62+72+...202 (3)12+(12+22)+(12+22+32)+...upto n terms. Please give proper methods. ...
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plz tell me all types of methods to find the sum of special series and all other types of series ...
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a NCERT ques.- if z1=2-i,z2=1+i, find modulus[(z1+z2+1)/(z1-z2+i)] ...
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A RELATION R IS DEFINED FROM A SET A={2,3,4,5} TO A SET B={3,6,7,10} AS FOLLOWS: R={(X,Y):X IS RELATIVELY PRIME TO Y} EXPRESS R AS A SET OF ORDERED PAIRS SOLUTION: R={(2,3),(2,7),(3,7),(3,10),(4,3),(4,7),(5,3),(5,6),(5,7)} IS ...
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Q2 Sin[ 2cos-1{cot(2tan-1 x)} ]= 0...... solve for positive value of x... a) x=1,√2-1,√2+1 b) x=1,12,13 c) x=1,√3-1,√3+1 d) x=√2+1,√3-1 ...
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in d world cup d tournament is arranged as per following rules in d beginning 16 teams r taken & divided into 2 groups of 8 each teams of each group play a match against each other in d same group from each group 4 top qualif ...
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1+x + x^2 .......................infinity = 1/1-x .......... integrate both sides .. x + x^2/2 + ............ = ln(1-x) - ln(1) put x = 1 ..... ln0 = 1+ 1/2 + 1/3 + 1/4 .................... [3] ...
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how to find the sum of the series- (1)x2+x4+x6+....+x2n (2)1/x2+1/x4+....1/x2n. Please tell in a proper stepwise manner. ...
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*Image* is such a que likely on 12th BTW if u know then pl give soltn i dont hav the answer ...
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Out of 46 consecutive integers two are chosen...find the probability that their sum is odd ...
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y = 16x2 + 8(a+5)x -7a -5 Find. prob of graf of y bein STRICTLY gr8er than ZERO for x ε [-20,0] PN : Ther is no condition given on a..... i dunno y........ i feel its an incomplete Questn .... if u tooo feel so do tell me ed ...
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*Image* mere ko ans nahi pata ...