1a+ c = 2b .........(1)
(b+c) + (a+b) = a + 2b + c = 2(a+c)
proved.
if a,b and c are in A.P then prove that,
(b + c), (c + a) and (a + b) are also in A.P
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4 Answers
36this is not what i wanted!!!!!
suppose u r given a,b and c are in A.P Now derive that,
(b + c), (c + a) and (a + b) are in A.P as well.... how will u solve it then?
21yup..do it like this
a,b,c in AP
a-(a+b+c) , b-(a+b+c), c-(a+b+c) in AP
-(b+c), -(a+c), -(a+b) in AP
b+c, c+a,a+b in AP
actually here we use properties that we think useless like adding/subtracting/multiplying/dividing same number with all terms of an AP gives an AP