Σ 1n4 = π4 90.......(1)
divide both sides by 24
so Σ 1(2n)4= π4 (90)16...(2)
subtract eqn 2 frm 1
so
114+134+154+... = π490(1-1/16)= 15π4(90)(16)
=Ï€496
If 114+124+134+.......∞ is π490, then 114+134+154+.......∞=
a)Ï€496
b)Ï€4100
c)Ï€4121
d)Ï€4108
Plz show the steps also as I dont even know how to start this prob...
here,Ï€ is pi.
Σ 1n4 = π4 90.......(1)
divide both sides by 24
so Σ 1(2n)4= π4 (90)16...(2)
subtract eqn 2 frm 1
so
114+134+154+... = π490(1-1/16)= 15π4(90)(16)
=Ï€496