RAJAT : [lovely solution!!!]
1 doubt : HOW DID U GET ((2^t - 1)/2^t)^r
i.e. in the very first line of ur expression........
RAJAT : [lovely solution!!!]
1 doubt : HOW DID U GET ((2^t - 1)/2^t)^r
i.e. in the very first line of ur expression........
tapan see:
if to take (to the power r) common then u have the terms 3/22, 7/23, ... = (2t-1)/2t
see. it is (22-1)/22, (23-1)/23, (24-1)/24 =(15/24)