for Q 1 hint : 4 + 11 = 7 + 8
if u dont get it then (1) take x+30/4 = t and solve or (2) expand (x+4)(x+11) and (x+7)(x+8) and write x2 + 15x = m,
for Q 1 hint : 4 + 11 = 7 + 8
if u dont get it then (1) take x+30/4 = t and solve or (2) expand (x+4)(x+11) and (x+7)(x+8) and write x2 + 15x = m,
the 1st one was discussed in detail here:
http://www.targetiit.com/iit-jee-forum/posts/solve-for-x-12309.html
that cannot be as f(-2) is obviously odd. As a start, from Rational Roots Theorem, check if we have root of the form p/q with p = ±1, or ±3 and q=±1, ±2
update: x=-3 is a root. The other roots are now easily obtained!
this one is not ad difficult either.... Based on same logic as in the first quesiton..
Just think upside down ;) :D
if there is a rational root of a plynmilla with integer/ rational coefficients then the root is a factor of last term/ first term...
no gaurav.. i confused it with the problem with only 1 4x-1..
I din read properly :P
please consider my ques whenever u r free n help me out wid d sol.