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plz crrect me if i m wrongg
(x+1)(x+2)(x+3) ........... (x+n)=A0 + A1x + A2x2 + ............Anxn.
Find A1 + 2A2 + 3A3 +.............nAn.
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4 Answers
106differentiate the expression and then put x=1
Im just calculating d(LHS)/dx
= (x+2)(x+3).....(x+n).1 + (x+1)(x+3)(x+4)...(x+n).1 .... +(x+1)(x+2)(x+3)...(x+n-1).1
= (x+1)(x+2)(x+3)...(x+n)[1/(x+1) + 1/(x+2) + 1/(x+3) + ...+ 1/(x+n)]
now put x=1
we get (n+1)!(1/2 + 1/3 + 1/4 + ... + 1/(n+1)]
1THNK U ASISH .........................GOT IT. FINALLY.......