An excellent question of Co-ordinate geometry and Algebra

eureka , anyone can commen. have some work to support what u said...

1/1!.9! +1/1!9! +1/3!7!+1/3!7! +1/5!5!

now multiply by 10! both sides

=>10C1 +10C3+10C5+10C7+10C9=2^m10!/n!
=>2^10-1/10!=2^m/n!

Eurie...one small error...it will be 10! rather than just 10... :-)

i have corrected that aveek

now
slope1=1,slope2=-1
=>perpendicular lines
=>orthocentre at intersection
=>P=(-2,-1)

fro mthe realtion we get m=9 ,n=10

=> orthocentre=(2m-2n,m-n)

b555...dont challenge me in those things I am damn sure.......I never write comments uselessly...unless i get mad .....

i hope u r not taking my comments seriuosly dude...[1]
i was just blabbering in this post

divide and multiply by 10!

u will get m=9 and n=10

now i think u can get orthocentre as (-50/3,-25/3)

i.e (-15n/m , -15n/2m )ans

ya i have sk goyal

only coordinate