Another remainder question

AIEEE 2015 Coaching › Algebra questions › Another remainder question

Find the least number which when

divided by-------------10--9--8--7--6--5--4--3--2--1
leaves remainder-----9--8--7--6--5--4--3--2--1--0

#Mathematics #Algebra

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Soumyadeep Basu ·2013-02-18 07:44:41

The lowest number divisible by 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 is their LCM which is 2520. Therefore, 2520-1 is div. by 1, 2520-2 is div. by 2.....2520-10 is div. by 10. Thus the reqd. number is 2520-1=2519.

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996

Swarna Kamal Dhyawala ·2013-02-18 07:22:53

the answer must be 2519

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Another remainder question

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