A coin has probability p of showing head when tossed.It is tossed n times.Let pn denote the probablity that no two(or more) consecutive heads appear.
Prove taht pn=(1-p)pn-1 +p(1-p)pn-2 for n≥3
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1 Answers
3we have two cases that is
1) when the last outcome is head then the outcome of the n-1 th toss shud be a tail and then we shudnt have ne consecutive heads or tails from 1 to n-2 th toss
2)when the last outcome is a tail then we shud have no consecutive heads in previous tosses
P(A)=p(1-p)pn-2+(1-p)pn-1
