9working backwards....
ending cases( A →B )
A B
1 n-1 ( For A to have 1 either it must start or it must ve got it frm another person which is impossible as it wud ve to be 0 then implying it already left table) so A starts is only possible ie n=2
A B
2 n-2 ( here someone must give A 1 penny or B itself gives)
ie
1 ) C gives A
C A B
1 1 n-2 here again C shud start in first place implying n=3
2) B gives A
A B
1 n-1
back 1 step A C B
1 2 n-3
back 1 step A D C B
1 1 1 n-3
which implies D has to start implying n=4
hence we can see n=1,2,3,4 alone satisfy
and THERE IS NO SUCH INFINITE SET as mentioned in the question !!!!!!
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