1oh no,so silly of me!i realized my mistake z=1.that's it!
if z=(1+2i)/{1-(1-i)2} then arg(z) is
1.0
2.pi/2
3.pi
4.none
me getting 2tan-12
-
UP 0 DOWN 0 0 3
3 Answers
1no 2tan-12 is not 0.
only just expand the denominator
1-(1-i)2= 1-(1-1-2i)
= 1+2i
thus net complex becomes 1
and arg of 1 is o