Based on BINOMIAL

show that

\frac{C_{0}}{1}-\frac{C_{1}}{5}+\frac{C_{2}}{9}-\frac{C_{3}}{13}+.........+(-1)^{n}\frac{C_{n}}{4n+1} = \frac{4^{n}n!}{1.5.9....(4n+1)}

2 Answers

oh ya but can u tell me the trick how u thght of taking \int_{0}^{1}{(1-x^{4})^{n}}dx for solving the abv question......

thnks dude

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