from, binomial expansion for any index, we have
(1+x)-3 = 1-3x + 6x2 - 10x3 ......
now replacing x with -x,
(1-x)-3 = 1+3x + 6x2 + 10x3 ......
The rth term is given by \frac{r(r+1)}{2}x^r-1
Now you want to find the sum
You can think of this as the derivative of something?
And then take the sum (Infact the double derivative?)
Give it a shot once...
Err , I think that -
Now , from the fundamentals of infinite G . P . - s ,
Differentiate each side of this identity twice to get -
from, binomial expansion for any index, we have
(1+x)-3 = 1-3x + 6x2 - 10x3 ......
now replacing x with -x,
(1-x)-3 = 1+3x + 6x2 + 10x3 ......