1how is this A2A1=n-2/2
A4A3=n-4/4
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2 Answers
62\\\frac{1}{1+\frac{A_2}{A_1}}+\frac{1}{1+\frac{A_4}{A_3}}-\frac{2}{1+\frac{A_3}{A_2}} \\\frac{1}{1+\frac{n-2}{2}}+\frac{1}{1+\frac{n-4}{4}}-\frac{2}{1+\frac{n-3}{3}} \\\frac{1}{\frac{n}{2}}+\frac{1}{\frac{n}{4}}-\frac{2}{\frac{n}{3}}=0