Binomial

Find the term independent of x in the expansion of
(x2/3+4x1/3+4)5 . [1/(x1/3-1) + 1/(x2/3+x1/3+1)]-9

4 Answers

13
MAK ·

simplifying d expression gives u...

(x-1)9 / x3.(x1/3+2)4

now, it can be solved by division...

1357
Manish Shankar ·

MAK you made a little mistake

see again power of the term (x1/3+2)

13
MAK ·

ohhh sorry... thx for correcting bro...

here's d correct expression...

(x1/3+2).(x-1)9 / x3

now solving it gives u d ans as

2.9C6 = 168

[1]

13
MAK ·

Explanation :

since x3 term is present in d denominator... the term independent of x will be d coefficient of x3 in numerator...

x1/3 doesn't result in x3 when multiplied wid any of d terms x,x2,...,x9

hence d coefficient of x3 in d numerator will be 2.(coefficient of x3 in (x-1)9)

= 2.9C6

=168...

[1]

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