Find the term independent of x in the expansion of
(x2/3+4x1/3+4)5 . [1/(x1/3-1) + 1/(x2/3+x1/3+1)]-9
13simplifying d expression gives u...
(x-1)9 / x3.(x1/3+2)4
now, it can be solved by division...
1357MAK you made a little mistake
see again power of the term (x1/3+2)
13ohhh sorry... thx for correcting bro...
here's d correct expression...
(x1/3+2).(x-1)9 / x3
now solving it gives u d ans as
2.9C6 = 168
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13Explanation :
since x3 term is present in d denominator... the term independent of x will be d coefficient of x3 in numerator...
x1/3 doesn't result in x3 when multiplied wid any of d terms x,x2,...,x9
hence d coefficient of x3 in d numerator will be 2.(coefficient of x3 in (x-1)9)
= 2.9C6
=168...
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