binomial

AIEEE 2015 Preparation › Algebra questions › binomial

If \frac{1}{\sqrt{4x+1}}\left( (\frac{1 + \sqrt{4x+1}}{2}) - (\frac{1 - \sqrt{4x+1}}{2})\right)^{n}

= ax + b x^2 + cx^3 + dx^4 + ex^5, then find n.

#Mathematics #Algebra

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Lokesh Verma ·2009-10-30 04:05:21

I guess you got stuck in a Googley :D

this is same as

\\\frac{1}{\sqrt{4x+1}}\left(\frac{\sqrt{4x+1} + \sqrt{4x+1}}2\right)^n \\=\frac{1}{\sqrt{4x+1}}(\sqrt{4x+1})^n \\=\frac{1}{\sqrt{4x+1}}(\sqrt{4x+1})^n \\=(\sqrt{4x+1})^{n-1}

Now what is the asnwer?

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cute_cat ·2009-10-30 09:51:17

k so ans is 11

thnx a lot sir

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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binomial

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